Statement: Add the contents of memory locations 40001H and 4001H and place the result in the memory locations 4002Hand 4003H.
Sample problem:
(4000H) = 7FH
(400lH) = 89H
Result = 7FH + 89H = lO8H
(4002H) = 08H
(4003H) = 0lH
Source program:
LXI H, 4000H :HL Points 4000H
MOV A, M :Get first operand
INX H :HL Points 4001H
ADD M :Add second operand
INX H :HL Points 4002H
MOV M, A :Store the lower byte of result at 4002H
MVIA, 00 :Initialize higher byte result with 00H
ADC A :Add carry in the high byte result
INX H :HL Points 4003H
MOV M, A :Store the higher byte of result at 4003H
HLT :Terminate program execution
